AD is the median of ΔABC. Therefore, it will divide ΔABC into two triangles of equal areas.
∴ Area (ΔABD) = Area (ΔACD)
⇒  ... (1)
  ... (1)
In ΔABD, E is the mid-point of AD. Therefore, BE is the median.
∴ Area (ΔBED) = Area (ΔABE)
⇒ Area (ΔBED) =  Area (ΔABD)
Area (ΔABD)
⇒ Area (ΔBED) =  Area (ΔABC) [From equation (1)]
Area (ΔABC) [From equation (1)]
⇒ Area (ΔBED) =  Area (ΔABC)
Area (ΔABC)